4c^2+9c-28=0

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Solution for 4c^2+9c-28=0 equation: 


Simplifying
4c2 + 9c + -28 = 0

Reorder the terms:
-28 + 9c + 4c2 = 0

Solving
-28 + 9c + 4c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-4 + -1c)(7 + -4c) = 0


Subproblem 1
Set the factor '(-4 + -1c)' equal to zero and attempt to solve:

Simplifying
-4 + -1c = 0

Solving
-4 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + -1c = 0 + 4

Combine like terms: -4 + 4 = 0
0 + -1c = 0 + 4
-1c = 0 + 4

Combine like terms: 0 + 4 = 4
-1c = 4

Divide each side by '-1'.
c = -4

Simplifying
c = -4

Subproblem 2
Set the factor '(7 + -4c)' equal to zero and attempt to solve:

Simplifying
7 + -4c = 0

Solving
7 + -4c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + -4c = 0 + -7

Combine like terms: 7 + -7 = 0
0 + -4c = 0 + -7
-4c = 0 + -7

Combine like terms: 0 + -7 = -7
-4c = -7

Divide each side by '-4'.
c = 1.75

Simplifying
c = 1.75
Solution
c = {-4, 1.75}

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